C^2+7c+12=(c+)(c+)

Solution for C^2+7c+12=(c+)(c+) equation:

^2+7C+12=(C+)(C+)

We move all terms to the left:

^2+7C+12-((C+)(C+))=0

We add all the numbers together, and all the variables

7C-((+C)(+C))+12+^2=0

We add all the numbers together, and all the variables

7C-((+C)(+C))=0

We multiply parentheses ..

-((+C^2))+7C=0


We calculate terms in parentheses: -((+C^2)), so:

(+C^2)

We get rid of parentheses

C^2

Back to the equation:

-(C^2)


We add all the numbers together, and all the variables

-1C^2+7C=0

a = -1; b = 7; c = 0;
Δ = b2-4ac
Δ = 72-4·(-1)·0
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$C_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$C_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$C_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-7}{2*-1}=\frac{-14}{-2}
=+7
$
$C_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+7}{2*-1}=\frac{0}{-2}
=0
$